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Neon gas is generally used in the sign boards. If it emits with wavelength of 616 nm, calculate (i) the frequency of emission (ii) energy of quantum and (iii) distance travelled by this radiation in 30 s. |
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Answer» Solution :`lambda_("Neon") = 16nm=616xx10^(-9)m` i) `v_("Neon")=(c)/(lambda)=(3XX10^(8)m.s^(-1))/(616xx10^(-9)m)=0.00487xx10^(17)s^(-1)` `=4.87xx10^(14)s^(-1)" (or Hertz)"` II) `E=hv=6.625xx10^(-34)J.s xx4.87xx10^(14)s^(-1)` `=32.26xx10^(-20)J` iii) `"distance travelled "= "Velocity "xx "time "=` `3xx10^(8) m.s^(-1)xx30s = 90 xx10^(8) m = 90 xx 10^(5) KM`. |
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