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Neongas isgenerally used in the signboards.ifit emitsstronglyat 616nmcalculate(a ) thefrequencyof emission( b)distancetraveledbythis radiationin 30s (c )energyof quantumand ( d)numberof quantapresentif itproduces2 J ofenergy . |
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Answer» SOLUTION :(a ) Frequencyof emission `V=(C )/(lambda)= (3.0 xx 10^ (8) MS^(-1))/(616 xx 10^(9) m)` ( b) Distancetraveledby thisradiationin 30s (d ) d=velocityof light`xx ` time `=3.0 xx 10^(8)ms^(-1)xx 30 s` `=9.0 xx 10^(9)m` =`900` carormeter= `(xx 10^(8) km)` (c )Quantum energy(E ) : `E= (hc )/( lambda )= (6.626 xx 10^(34)J s3.0 xx 10^(8) ms^(-1))/(616 xx 10^(9) m)` (d ) Numberof quanta in 2 J of energy (N ) : N=`("TOTAL energy ")/(" 1 quantum energy ") = (2J )/( 3.23 xx 10^(19))` `=6.192 xx 10^(18)` Numberof quantum |
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