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Nernst equation is `E = E^(@)-(RT)/(nF)lnQ`. If `Q = K_(C)`, then which one is one correct,A. `E = E^(@)`B. `(RT)/(nF)lnQ = E^(@)`C. `E = 0`D. `K_(C) = e^((nE^(@)F)/(RT))` |
Answer» Correct Answer - A If `Q = K_(c)`, then `E = 0` Also `E^(@) = (RT)/(nF)lnK_(c)` `K_(c) = e^(nF^(@)F//RT)` |
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