nerpendicularAD on the base BC of athe. Thef th Prove that 2AB2 2AC2+

1.	nerpendicularAD on the base BC of athe. Thef th Prove that 2AB2 2AC2+ BC2AABC intersects BC at D so that DB 3CD.ly..MOCK TEST PAPER257
Answer» Let BD = 3y , CD = y, and thus BC = 4y. Applying Pythagoras theorem, In ∆ABD , AB² = AD²+BD² In ∆ACD, AC² = AD²+CD², from equations above equate for AD, we get, AB²–BD² = AC²–CD² AB² = AC² + 9y²–y²= AC² + 8y²multiply by 2, 2AB² = 2AC²+16y²which is, 2AB² = 2AC² + BC² Like my answer if you find it useful!

nerpendicularAD on the base BC of athe. Thef th Prove that 2AB2 2AC2+ BC2AABC intersects BC at D so that DB 3CD.ly..MOCK TEST PAPER257

Answer»

Let BD = 3y , CD = y, and thus BC = 4y.

Applying Pythagoras theorem,

In ∆ABD , AB² = AD²+BD²

In ∆ACD, AC² = AD²+CD²,

from equations above equate for AD, we get,

AB²–BD² = AC²–CD²

AB² = AC² + 9y²–y²= AC² + 8y²multiply by 2,

2AB² = 2AC²+16y²which is,

2AB² = 2AC² + BC²

Like my answer if you find it useful!