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Neutralisation constant of HCOOH with a strong bse is 10^(8). What is the pH of 0.01 M HCOOK solution at 25^(0)C? |
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Answer» `K_("neu") = (1)/(K_(h)) = (K_(a))/(K_(w))` `K_(a) = 10^(8) xx 10^(-14) = 10^(-6) , pH = 7+3-1 = 9` |
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