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neutralization of 50 cm cube of 1 molar Sodium Hydroxide at 50 degrees with 1 molar hydrochloric acid 25 degree Celsius is raised to 35 degree celsius the specific heat of water is 5.0 per joule per kg find the enthalpy of neutralization |
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Answer» J500 cm3 of 0.1 M HCl corresponds to 0.5×0.1=0.05 moles of HYDROGEN ions.200 cm3 of 0.2 M NaOH corresponds to 0.2×0.2=0.04 moles of hydroxide ions.sodium hydroxide is COMPLETELY neutralize by HclThe ENTHALPY of neutralisation is 57.3 KJ/mol. For 0.04 moles, the enthalpy of neutralisation is 0.04×57.3=2.292 kJ |
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