1.

Newton's law of cooling states that the rate of change of the temperature T of an object isproportional to the difference between T and the (constant) temperature tau of the surrounding medium, we can write it as (dT)/(dt) = -k(T - tau) k gt 0 constant An cup of coffee is served at 185^(@)F in a room where the temperature is 65^(@)F. 2 minutes later the temperature of the coffee has dropped to 155^(@)F. log_(e)3 = 1.09872, log_(e).(3)/(4) = 0.2877 The temperature of any object at t = 2 is

Answer»

`tau e^(-k) + [ T(0)] e^(-2K)`
`tau e^(k) + [T(0) - tau] e^(-2k)`
`tau+[T(0) - tau] e^(-2k)`
`tau + 2[T(0)+tau] e^(-)`

Answer :C


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