1.

NH_(3) is formed in the following steps I. Ca+2CrarrCaC_(2) 50% yield II. CaC_(2)+N_(2)rarrCaCN_(2)+C 100% yield III. CaCN_(2)+3H_(2)Orarr2NH_(3)+CaCO_(3) 50% yield To obtain 2 moles NH_(3), calcium required is

Answer»

1 MOL
2 mol
3 mol
4 mol

Solution :`Ca+2CrarrCaC_(2)`
`100rarr50`
`CaC_(2)+N_(2)rarrCaCN_(2)+C`
`50rarr50`
`CaCN_(2)+3H_(2)Orarr2NH_(3)+CaCO_(3)`
`50rarr100xx(50)/(100)=50`
`therefore CararrNH_(3)`
`100rarr50`
`?rarr2 =4mol`


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