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NH_(3) is formed in the following steps I. Ca+2CrarrCaC_(2) 50% yield II. CaC_(2)+N_(2)rarrCaCN_(2)+C 100% yield III. CaCN_(2)+3H_(2)Orarr2NH_(3)+CaCO_(3) 50% yield To obtain 2 moles NH_(3), calcium required is |
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Answer» Solution :`Ca+2CrarrCaC_(2)` `100rarr50` `CaC_(2)+N_(2)rarrCaCN_(2)+C` `50rarr50` `CaCN_(2)+3H_(2)Orarr2NH_(3)+CaCO_(3)` `50rarr100xx(50)/(100)=50` `therefore CararrNH_(3)` `100rarr50` `?rarr2 =4mol` |
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