1.

(NH_4)_2 CO_(3(s)) hArr 2NH_(3(g)) + CO_(2(g)) + H_2O_((g)) If the total pressure is P at equilibrium then what will be the volume of equilibrium constant, K_p in a closed vessel ?

Answer»

<P>`P^4/64`
`P^3/32`
`(4P^3)/27`
`P^3/64`

Solution :TOTAL pressure =P
`K_P=(P_(NH_3))^2 xx (P_(CO_2))xx(P_(H_2O))`
`=((2P)/4)^2 xx (P/4) xx (P/4)=P^4/64`


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