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NH_(4)HS(s)hArrNh_(3)(g)+H_(2)S(g) K_(P_(1) NH_(3)(g)hArr(1)/(2)N_(2)(g)+(3)/(2)H_(2)(g) K_(P_(2) 2 mol NH_(4)HS(s) is taken & 50% of this is dissociated till at equilibrium in 1 litre container. Find (K_(P_(2)^(2)))/(K_(P_(1)^(6)) if 0.25 moles of N_(2) are found finally. |
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