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`NH_4COONH_2 (s) hArr 2NH_3(g)+CO_(2)(g)` If equilibrium pressure is 6 atm for the above reaction, `K_p` will be :A. 32B. 27C. `4//27`D. `1//27` |
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Answer» Correct Answer - A `NH_4COONH_2(s)hArrunderset(2p)(2NH_(3)(g))+undersetp(CO_(2)(g))` 2p+p=6 p=2 atm `:. P_(NH_3)=4` atm , `P_(CO_2)=2` atm `K_(p)=[P_(NH_3)]^2[P_(CO_2)]=4^2xx2=32` |
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