`Ni(s) + Cu^(2+)(aq) rightarrow Ni^(2+)(aq) + Cu(s)` The voltaic cell based on this reaction has a voltage of 0.59 V under standard conditions. Which of these changes will produce a higher voltage? (P) Increasing `[Cu^(2+)]` (Q) Increasing the size of the `Ni(s)` electrode.A. P onlyB. Q onlyC. Both P and QD. Neither P nor Q

`Ni(s) + Cu^(2+)(aq) rightarrow Ni^(2+)(aq) + Cu(s)` The voltaic cell

1.	`Ni(s) + Cu^(2+)(aq) rightarrow Ni^(2+)(aq) + Cu(s)` The voltaic cell based on this reaction has a voltage of 0.59 V under standard conditions. Which of these changes will produce a higher voltage? (P) Increasing `[Cu^(2+)]` (Q) Increasing the size of the `Ni(s)` electrode.A. P onlyB. Q onlyC. Both P and QD. Neither P nor Q
Answer» Correct Answer - A

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The EMF of the following cell: `Zn| Zn^(2+)(0.1M) || Cl^(-)(0.01M) | AgCl | Ag` is: [Given : E_(Zn^(2+)|/Zn)^(@) = -0.76V`, `E_(Cl^(-)| AgCl|Ag)^(@)` = 0.22 V`, `(2.303RT)/(F) = 0.06]`A. 0.96 VB. 0.345 VC. 1.23D. 1.13 V
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