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Nicker crystallizes in an fcc unit cell with a cell-edge length of 0.3524nm. Calcualte the radius of the nickel atomA. 0.1624nmB. 0.1246nmC. 0.2164nmD. 0.1426nm |
Answer» Correct Answer - B For an fcc lattice, `d_("face")=asqrt(2)` or `4r_(Ni)=asqrt(2)` `r_(Ni)=(asqrt(2))/(4)=sqrt(2)/(4)xx0.3524=0.1246` nm |
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