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Nickle crystallise in a fcc unit cell with a cell edge length of 0.3524 nm. Calculate the radius of the nicke atomA. 0.1624 nmB. 0.1246 nmC. 0.2164 nmD. 0.1426nm |
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Answer» Correct Answer - B For an fcc lattice , `r=(a)/(2sqrt2)=(0.3524)/(2sqrt2)` = 0.1246nm` |
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