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निकालिए `1+(1)/(2)+(1)/(4)+(1)/(8)+..........` अनन्त तक `("to "oo)` |
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Answer» यहाँ `a=1,r=(1)/(2).(rlt1)` अब `S_(oo)=(a)/(1-r)=(1)/(1-(1)/(2))=2`. |
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