InterviewSolution
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निम्न रेखाओं के बीच की न्यूनतम दुरी ज्ञात कीजिए- `vecr=(3hati+5hatj+7hatk)+lambda(hati-2hatj+7hatk)` तथा `vecr=-hati-hatj-hatk+mu(7hati-6-hatj-hatk)` |
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Answer» माना `veca_(1)=3hati+5hatj+7hatk,vecb_(1)=hati-2hatj+hatk` `a_(2)=-hati-hatj-hatk,vecb_(2)=7hati-hat6j+hatk` `:. veca_(1)-vecb_(1)=-4hati-6hatj-8hatk` तथा `vecb_(1)xxvecb_(2)=|{:(hati,hatj,hatk),(1,-2,7),(7,-6,1):}|=40hati+48hatj+8hatk` `rArr |vecb_(1)xxvecb_(2)|=sqrt((40^(2))+(48)^(2)+(8)^(2))=sqrt(3968)` अब `(veca_(2)-veca_(1))*(vecb_(1)xxvecb_(2))` `=(-4hati-6hatj-8hatk)*(40hati+48hatjj+8hatk)` `=(-4)(40)+(-6)(48)+(-8)(8)=-512` इसलिए, अभीष्ट न्यूनतम दुरी `=|(-512)/(sqrt(3968))|=(64)/(sqrt(62))` इकाई |
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