1.

निम्न रेखाओं के बीच की न्यूनतम दुरी ज्ञात कीजिए- `vecr=(3hati+5hatj+7hatk)+lambda(hati-2hatj+7hatk)` तथा `vecr=-hati-hatj-hatk+mu(7hati-6-hatj-hatk)`

Answer» माना `veca_(1)=3hati+5hatj+7hatk,vecb_(1)=hati-2hatj+hatk`
`a_(2)=-hati-hatj-hatk,vecb_(2)=7hati-hat6j+hatk`
`:. veca_(1)-vecb_(1)=-4hati-6hatj-8hatk`
तथा `vecb_(1)xxvecb_(2)=|{:(hati,hatj,hatk),(1,-2,7),(7,-6,1):}|=40hati+48hatj+8hatk`
`rArr |vecb_(1)xxvecb_(2)|=sqrt((40^(2))+(48)^(2)+(8)^(2))=sqrt(3968)`
अब `(veca_(2)-veca_(1))*(vecb_(1)xxvecb_(2))`
`=(-4hati-6hatj-8hatk)*(40hati+48hatjj+8hatk)`
`=(-4)(40)+(-6)(48)+(-8)(8)=-512`
इसलिए,
अभीष्ट न्यूनतम दुरी `=|(-512)/(sqrt(3968))|=(64)/(sqrt(62))` इकाई


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