InterviewSolution
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InterviewSolution
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निम्न समीकरण को हल कीजिए - ` sin^(-1)x+sin^(-1)2x=(pi)/(3)` |
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Answer» `sin^(-1)x+sin^(-1)2x=sin^(-1)""(sqrt(3))/(2)` `implies sin^(-1)x-sin^(-1)((sqrt(3))/(2))=-sin^(-1)(2x)` `implies sin^(-1)[xsqrt(1-(3)/(4))-(sqrt(3))/(4)sqrt(1-x^(2))]=sin^(-1)(2x)` `implies (x)/(2)-(sqrt(3))/(2)sqrt(1-x^(2))=-2x` `implies (5x)/(2)=(sqrt(3))/(2)sqrt(1-x^(2))` `implies 5x=sqrt(3)*sqrt(1-x^(2))implies 25x^(2)=3(1-x^(2))` `implies 28x^(2)=3impliesx^(2)=(3)/(28)` `:. x= pm(1)/(2)sqrt((3)/(7))` परन्तु `x=(-1)/(2)sqrt((3)/(7))` दी गयी समीकरण को संतुष्ट नहीं करता इसलिए `x=(1)/(2)sqrt((3)/(7))` दी गयी समीकरण का हल है । |
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