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InterviewSolution
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निम्नलिखित आंकड़ों से `CH_(3)OH(l)` की मानक - विरचन एन्थैल्पी ज्ञात कीजिए - `CH_(3)OH(l) + 3/2 O_(2)(g) rarr CO_(2)(g) + 2H_(2)O(l),` `Delta_(r)H^(@) = - 726 kJ "mol"^(-1)` `C(g) + O_(2)(g) rarr CO_(2)(g) , Delta_(f)H^(@) = - 393 kJ "mol"^(-1)` `H_(2)(g) + 1/2O_(2)(g) rarr H_(2)O (l) , Delta_(f)H^(@) = - 286 kJ "mol"^(-1)` |
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Answer» दिये गए आँकड़ो के अनुसार, `Delta_(c)H^(@) [CO_(2)(g)] = Delta_(f)H^(@)[CO_(2)(g)] = - 393 kJ "mol"^(-1)` `:. Delta_(r) H^(@) = sumDelta_(f)H^(@)("उत्पाद")-sumDelta_(f)H^(@) ("अभिकारक")` या `Delta_(r) H^(@) = {Delta_(f)H^(@) [CO_(2)(g)] + 2xx Delta_(f)H^(@)[H_(2)O(l)]}` ` - {DeltaH_(f)^(@) [CH_(3)OH(l)]+3/2 xx Delta_(f)H^(@)[O_(2)(g)]` या `-726 = {-393+2xx(-286)} - {Delta_(f)H^(@) [CH_(3)OH(l)]+3/2 xx 0}` या `- 726 =(-965) - Delta_(f)H^(@) [CH_(3)OH(l)]` या `Delta_(f)H^(@)[CH_(3)OH(l)] = + 726 - 965 = - 239 kJ "mol"^(-1)` |
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