InterviewSolution
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InterviewSolution
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निम्नलिखित सारणिक के अवयवों के उपसारणिक एवं सहखण्ड लिखिए। `|(1,0,0),(0,1,0),(0,0,1)|` |
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Answer» (i) माना `A=|(1,0,0),(0,1,0),(0,0,1)|` उपसारणिक `M_(11)=|(1,0),(0,1)|=-1-0=1` `M_(12)=|(0,0),(0,1)|=0-0=0,M_(13)=|(0,1),(0,0)|=0-0=0` `M_(21)=|(0,0),(0,1)|=0-0=0,M_(22)=|(1,0),(0,1)|=1-0=1` `M_(23)=|(1,0),(0,0)|=0-0=0` `M_(31)=|(0,0),(1,0)|=0-0=0,M_(32)=|(1,0),(0,0)|=0-0=0` `M_(33)=|(1,0),(0,1)|=1-0=1` सहखण्ड `A_(11)=(-1)^(1+1)M_(11)=1,A_(12)=(-1)^(1+2)M_(12)=0` `A_(13)=(-1)^(1+3)M_(13)=0` `A_(21)=(-1)^(2+1)M_(21)=0,A_(22)=(-1)^(2+2)M_(22)=1` `A_(23)=(-1)^(2+3)M_(23)=0` `A_(31)=(-1)^(3+1)M_(31)=0,A_(32)=(-1)^(3+2)M_(32)=0` `A_(33)=(-1)^(3+3)M_(33)=1` (ii) माना `A=|(1,0,4),(3,5,-1),(0,1,2)|` उपसारणिक `M_(11)=|(5,-1),(1,2)|=10+1=11` `M_(12)=|(3,-1),(0,2)|=6-0=6,M_(13)=|(3,5),(0,1)|=3-0=3` `M_(21)=|(0,4),(1,2)|-0-4=-4,M_(22)=|(1,4),(0,2)|=2-0=2` `M_(23)=|(1,0),(0,1)|=1-0=1` `M_(31)=|(0,4),(5,-1)|=0-20=-20` `M_(32)=|(1,4),(3,-1)|=-1-12=-13` `M_(33)=|(1,0),(3,5)|=5-0=5` सहखण्ड `A_(11)=(-1)^(1+1)M_(11)=11` `A_(12)=(-1)^(1+2)M_(12)=-6,A_(13)=(-1)^(1+3)M_(13)=3` `A_(21)=(-1)^(2+1)M_(21)=4,A_(22)=(-1)^(2+2)M_(22)=2` `A_(23)=(-1)^(2+3)M_(23)=-1` `A_(31)=(-1)^(3+1)M_(31)=-20,A_(32)=(-1)^(3+2)M_(32)=13`, `A_(33)=(-1)^(3+3)M_(33)=5` |
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