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निम्नलिखित समीकरण को हल कीजिए - `tan^(-1)((1-x)/(1+x))=(1)/(2)tan^(-1)x, (x gt0).` |
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Answer» यहाँ `tan^(-1)((1-x)/(1+x))=(1)/(2)tan^(-1)x` `x=tan theta` रखने पर `tan^(-1)[(1-tan theta)/(1+tan theta)]=(1)/(2)tan^(-1)(tan theta)` `rArr tan^(-1)[(tan.(pi)/(4)-tan theta)/(1+tan.(pi)/(4)tan theta)]=(1)/(2)theta` `rArr tan^(-1)[tan((pi)/(4)-theta)]=(1)/(2)theta,` `" "[because tan(A-B)=(tan A-tanB)/(1+tanA tanB)]` `rArr" "(pi)/(4)-theta=(1)/(2)theta` `rArr" "(3)/(2)theta=(pi)/(4)` `rArr" "theta=(pi)/(6)` `rArr" "tan^(-1)x=((pi)/(6))` `rArr" "x=(1)/(3).` |
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