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निम्नलिखित समीकरण को हल कीजिए - `tan^(-1)(cotx)+cot^(-1)(tanx)=(pi)/(4)` |
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Answer» दिया गया समीकरण है - `tan^(-1)(cotx)+cot^(-1)(tanx)=(pi)/(4)` `tan^(-1)[tan((pi)/(2)-x)]+cot^(-1)[cot((pi)/(2)-x)]=(pi)/(4),` `[because tan((pi)/(2)-x)=cotx , cot((pi)/(2)-x)=tanx]` `(pi)/(2)-x+(pi)/(2)-x=(pi)/(4)` `=(pi)/(2)+(pi)/(2)-(pi)/(4)=2x` `(pi)/(2)+(pi)/(2)-(pi)/(4)=2x` `2x=(3pi)/(4) rArr x =(3pi)/(8).` |
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