InterviewSolution
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निम्नलिखित समीकरण निकाय को हल कीजिए। `2/x+3/y+10/z=4` `4/x-6/y+5/z=1``6/x+9/y-20/z=2` |
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Answer» माना `1/x=p,1/y=q,1/z=r` `:.` दिया गया समीकरण निकाय `2p+3q+10r=4` ltbgt `4p-6q+5r=1` `6p+9q-20r=2` `implies[(2,3,10),(4,-6,5),(6,9,-20)][(p),(q),(r)]=[(4),(1),(2)]impliesAX=B`…………..1 `:.A[(2,3,10),(4,-6,5),(6,9,-20)]` `=2(120-45)-3(-80-30)+10(36+36)` `=150+330+720=1200!=0` `impliesA` व्युत्क्रमणीय है। `A_(11)=75,A_(12)=110,A_(13)=72` `=A_(21)=150,A_(22)=100,A_(23)=0` `A_(31)=75,A_(32)=30,A_(33)=-24` `:.adjA=[(75,110,72),(150,-100,0),(75,30,-24)]` `=[(75,150,75),(110,-100,30),(72,0,-24)]` तथा `A^(-1)=1/(|A|).adjA=1/1200[(75,150,75),(110,-100,30),(72,0,-24)]` समीकरण 1 से `AX=BimpliesX=A^(-1)B` `implies[(p),(q),(r)]=1/1200[(75,150,75),(110-100,30),(72,0,-24)][(4),(1),(2)]` `=1/1200[(300+150+150),(440-100+60),(288+0-48)]=[(1/2),(1/3),(1/5)]` `implies p=1/2,q=1/3,r=1/5` `implies1/x=1/2,1/y=1/3,1/z=1/5` `impliesx=2,y=3,z=5` |
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