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निम्नलिखित समीकरणों को हल कीजिए - `2tan^(-1)(cosx)=tan^(-1)("2 cosec x").` |
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Answer» दिया गया समीकरण है - `2tan^(-1)(cosx)=tan^(-1)("2 cosec x")` `rArr tan^(-1)((2cos x)/(1-cos^(2)x))=tan^(-1)((2)/(sinx))` `" "[because 2 tan^(-1)x=tan^(-1)((2x)/(1-x^(2)))]`. `rArr" "(2cosx)/(1-cos^(2)x)=(2)/(sinx)` `rArr" "(2cos x)/(sin^(2)x)=(2)/(sinx)` `rArr" "cos x=sinx` `rArr" "tanx=1` `rArr" "x=tan^(-1)(1)` `rArr" "x=tan^(-1)(tan.(pi)/(4))` `rArr" "x=(pi)/(4).` |
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