1.

Niobium crystallises in body-centred cubic structure. If the atomic radius is 143.1 pm, calculate the density of Niobium (Atomic mass=93u )

Answer»


SOLUTION :For bcc, `r=sqrt3/4a` or `a="4r"/3=(4xx143.1)/(1.732)`pm =330.5 pm
`RHO=(ZxxM)/(a^3xxN_0)=(2xx93)/((330.5xx10^(-10))^3XX(6.02xx10^23))=8.6 "G cm"^(-3)`


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