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Niobium crystallises in body-centred cubic structure. If the atomic radius is 143.1 pm, calculate the density of Niobium. (Atomic mass = 93u). |
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Answer» `r = (sqrt(3))/(4)a` `143.1 = (sqrt(3))/(4)a` a = 330.4 pm `rho = (zM)/(a^(3)N_(A))` `rho = (2 xx 93)/((330.4 xx 10^(-10)) xx 6.023 xx 10^(23))` `p = 8.58 g//cm^(3)`. |
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