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Niobium crystallizes in body-centred cubic structure. If the density is `8.55 g cm^(-3)`, calculate the atomic radius of niobium using its atomic mass `93 u`.A. 143pmB. 331pmC. 190pmD. 300pm |
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Answer» Correct Answer - 1 `a^(3)=3.31xx10^(-24)cc` `a=3.31xx10^(-8)cm=331pm` `r=(sqrt(3)a)/(4)=143pm` |
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