Nitric acid can be produced from NH_(3) in three step process I) 4NH_(3(g))+5O_(2(g))rarr4NO_((g))+6H_(2)O_((g)) II) 2NO_((g))+O_(2(g))rarr2NO_(2(g)) III) 3NO_(2(g))+H_(2)O_((l))rarr2HNO_(3(aq))+NO_((g)) % yield of I, II, III reaction are respectively 50%, 60%and 80%. Then how much volume of NH_(3(g)) at STP is required to produce 2.25 gm of HNO_(3).

Nitric acid can be produced from NH_(3) in three step process I) 4NH_

1.	Nitric acid can be produced from NH_(3) in three step process I) 4NH_(3(g))+5O_(2(g))rarr4NO_((g))+6H_(2)O_((g)) II) 2NO_((g))+O_(2(g))rarr2NO_(2(g)) III) 3NO_(2(g))+H_(2)O_((l))rarr2HNO_(3(aq))+NO_((g)) % yield of I, II, III reaction are respectively 50%, 60%and 80%. Then how much volume of NH_(3(g)) at STP is required to produce 2.25 gm of HNO_(3).
Answer» Solution :`4NH_(3)+5O_(2)rarr4NO+6H_(2)O,50%` `100rarr50` `2NO+O_(2)rarr2NO_(2),60%` `50 rarr50xx(60)/(100)=30` `3NO_(2)+H_(2)Orarr2HNO_(3)+NO,80%` `30rarr20xx(80)/(100)=16` 100 moles `NH_(3)=16` moles `HNO_(3)` `?larr (2.25)/(63)` moles `V_(NH_(3))` at STP = `(2.25xx100)/(63xx16)xx22.4=5`