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Nitrogen forms 2 oxides in which mass percentage of oxygen is 63.15% and 74.07% respectively. Write their emperical formulae. I need answer with full and detailed process. |
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Answer» ANSWERLet us consider a sample containing 100 g NxOyFor N⇒x×14= 100100×25.94 ⇒x=1.85For O⇒y×16= 100100×74.09 ⇒y=4.63So, N 1.85 O 4.63 ⇒N 2 O 5 (Empirical Formula)EXPLANATION:PLEASE mark me as brainliest and follow me on |
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