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Nitrogen laser produces a radiation at a wavelength of 337.1 nm. If the number of photons emitted is 5.6 x 1024 per second, calculate the power of this laser. |
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Answer» Energy of photos emitted in 1 s =Nhu = Nh\(\frac{C}{\lambda}\) \(\frac{5.6\times10^{24}s^{-1}\times 6.626\times10^{-34}Js\times 3\times 10^3ms^{-1}}{337.1\times 10^{-9}m}\) = 33Js-1 |
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