1.

Nitrogen laser produces a radiation at a wavelength of 337.1 nm. If the number of photons emitted is 5.6 x 1024 per second, calculate the power of this laser.

Answer»

Energy of photos emitted in 1 s =Nhu = Nh\(\frac{C}{\lambda}\) 

\(\frac{5.6\times10^{24}s^{-1}\times 6.626\times10^{-34}Js\times 3\times 10^3ms^{-1}}{337.1\times 10^{-9}m}\) 

= 33Js-1



Discussion

No Comment Found

Related InterviewSolutions