1.

Nitrogenlaserproducesa radiationat a wavelengthof 337.1nmifthe numberofphotonsemitted is 5.6 xx 10^(24) calculatethepowerof thislaser.

Answer»

Solution :Emittedlaser energy`(E ) = (hc )/(lambda)`andNumberof photon=Nlaserenergy`=E_(p)`
`:. , E_(p)= (Nhc )/( lambda)`
`=(5.6 xx 10^(24)6.626 xx 10^(34)js 3.0 xx 10^(8) MS^(-1))/((337.1 xx 10^(9) m))`
`0.3302xx 10^(7) `
`=3.302 xx 10^(6) J` emittedlaserenergy


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