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Nitrogenlaserproducesa radiationat a wavelengthof 337.1nmifthe numberofphotonsemitted is 5.6 xx 10^(24) calculatethepowerof thislaser. |
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Answer» Solution :Emittedlaser energy`(E ) = (hc )/(lambda)`andNumberof photon=Nlaserenergy`=E_(p)` `:. , E_(p)= (Nhc )/( lambda)` `=(5.6 xx 10^(24)6.626 xx 10^(34)js 3.0 xx 10^(8) MS^(-1))/((337.1 xx 10^(9) m))` `0.3302xx 10^(7) ` `=3.302 xx 10^(6) J` emittedlaserenergy |
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