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nlu nf k ?k k t 10 and 3k + 2 are in A.P.?

Answer»

Let a1= 2k, a2= k+10, a3= 3k+2 are in AP, then

Second term - first term = third term - second term

K+10 -(2k) = 3k+2-(k+10)

K+10-2k =3k+2-k-10

k -2k +10 = 3k-k +2-10

-k +10= 2k -8

-k-2k= -8-10

-3k = -18

k =18/3= 6

k= 6

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