Saved Bookmarks
| 1. |
nlu nf k ?k k t 10 and 3k + 2 are in A.P.? |
|
Answer» Let a1= 2k, a2= k+10, a3= 3k+2 are in AP, then Second term - first term = third term - second term K+10 -(2k) = 3k+2-(k+10) K+10-2k =3k+2-k-10 k -2k +10 = 3k-k +2-10 -k +10= 2k -8 -k-2k= -8-10 -3k = -18 k =18/3= 6 k= 6 Like my answer if you find it useful! |
|