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No. Of electrons in 2.8 g ethene is

Answer» Molar mass of C2H4 (ethene) = 2×12+4×1 = 28 gMoles of ethene = Given mass / Molar mass =2.8g/28g mol^-1 =0.1 mol1 mole = 6.022 × 10^23 atoms0.1 mole = (6.022 ×10^23 atoms/1 mole)× 0.1 mole = 6.022 ×10^22 atoms 1 atom of C2H4 has electrons = 106.022×10^22 atoms of C2H4 have electrons = 6.022 ×10^22 ×10 = 6.022 ×10^22 electrons


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