No. of H_(2)O molecules in a drop of water weighing 0.05 g is :

1.	No. of H_(2)O molecules in a drop of water weighing 0.05 g is :
Answer» `1.15 xx 10^(23)` `1.672 xx 10^(21)` `1.5 xx 10^(20)` `6.022 xx 10^(22)` Solution :18.0 g of `H_(2)O` contain molecules `=6.022 xx 10^(23)` 0.05 g of `H_(2)O` contain molecules `= ((0.05g))/((18.0g))xx6.022xx10^(23)` `=1.673xx10^(21)` molecules.

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