1.

No. of moles in 100 mg of heptane is …………than those in 10 mg of propyne

Answer»

4 times greater
4 times lesser
2.5 times greater
2.5 times lesser

Solution :No. of moles in 100 mg of heptane `(C_(7)H_(16))`
`= ((100xx10^(-3)g))/(("100g mol"^(-1)))=1xx10^(-3)`
No. of moles in 10 mg of PROPYNE `(C_(3)H_(4))`
`= ((10xx10^(-3)g))/(("40 g mol"^(-1)))=(1)/(4)xx10^(-3)`
No. of moles of heptane are FOUR times the no. of moles of propyne.


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