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No. of moles in 100 mg of heptane is …………than those in 10 mg of propyneA. 4 times greaterB. 4 times lesserC. 2.5 times greaterD. 2.5 times lesser |
Answer» Correct Answer - A No. of moles in 100 mg of heptane `(C_(7)H_(16))` `= ((100xx10^(-3)g))/(("100g mol"^(-1)))=1xx10^(-3)` No. of moles in 10 mg of propyne `(C_(3)H_(4))` `= ((10xx10^(-3)g))/(("40 g mol"^(-1)))=(1)/(4)xx10^(-3)` No. of moles of heptane are four times the no. of moles of propyne. |
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