1.

No. of moles in 100 mg of heptane is …………than those in 10 mg of propyneA. 4 times greaterB. 4 times lesserC. 2.5 times greaterD. 2.5 times lesser

Answer» Correct Answer - A
No. of moles in 100 mg of heptane `(C_(7)H_(16))`
`= ((100xx10^(-3)g))/(("100g mol"^(-1)))=1xx10^(-3)`
No. of moles in 10 mg of propyne `(C_(3)H_(4))`
`= ((10xx10^(-3)g))/(("40 g mol"^(-1)))=(1)/(4)xx10^(-3)`
No. of moles of heptane are four times the no. of moles of propyne.


Discussion

No Comment Found

Related InterviewSolutions