1.

No of revolutions made by the electron in one sec in 2^(nd) orbit of Be^(3+)

Answer»

`1.31 XX 10^(16)`
`2.13xx10^(16)`
`1.23xx10^(15)`
`2.68xx10^(14)`

Solution :No. of revolutions (RPS) `=(Z^2)/(n^3) (6.65xx10^(15)) Hz`


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