Noble gases have compleately filled valance shall i.e. `m^(2)sp^(2)` exceps He (i.e) .Noble gases are monoomic under normal conductions .Law bolding point of the ligher noble gases are due to weak van dor wads forces between the atoms and abance of any interature imaractions `Xe` reacts with `F_(2)` so give a sourceof fouoxide mently `XeF_(2),XeF_(4),XeF_(4),XeF_(3)` on complete hydrolyes gives `XeFe_(3)`, Oxidetion state of `Xe` in `XeF_(2)` isA. `+2`B. `+4`C. `+6`D. `+8`

Noble gases have compleately filled valance shall i.e. `m^(2)sp^(2)` e

1.	Noble gases have compleately filled valance shall i.e. `m^(2)sp^(2)` exceps He (i.e) .Noble gases are monoomic under normal conductions .Law bolding point of the ligher noble gases are due to weak van dor wads forces between the atoms and abance of any interature imaractions `Xe` reacts with `F_(2)` so give a sourceof fouoxide mently `XeF_(2),XeF_(4),XeF_(4),XeF_(3)` on complete hydrolyes gives `XeFe_(3)`, Oxidetion state of `Xe` in `XeF_(2)` isA. `+2`B. `+4`C. `+6`D. `+8`
Answer» Correct Answer - a `XeF_(2) x + (-1) xx 2 = 0 rArr s = +2` oxidation state of `Xe` in `XeF_(2)` is `+ 2`