Normal water is mainly protium oxide, H_(2)O However, if protium atoms in normal water molecule are replaced completely by deuterium atoms, the resulting water is called heavy water. The ionization constant of protum water (H_(2)O hArr H^(+)+OH) is 1xx10^(-14) and that in heavy water (D_(2)O hArr OD^(-)) is 3xx10^(-15) is 3xx10^(-15) H_(2)O dissociates about

Normal water is mainly protium oxide, H_(2)O However, if protium atoms

1.	Normal water is mainly protium oxide, H_(2)O However, if protium atoms in normal water molecule are replaced completely by deuterium atoms, the resulting water is called heavy water. The ionization constant of protum water (H_(2)O hArr H^(+)+OH) is 1xx10^(-14) and that in heavy water (D_(2)O hArr OD^(-)) is 3xx10^(-15) is 3xx10^(-15) H_(2)O dissociates about
Answer» THREE TIMES as MUCH as `D_(2)O` does thirty times as much as `D_(2)O` does `0.3` times as much as `D_(2)O` does 300 times as much as `D_(2)O` does Solution :`((K_(W))_(H_(2)O))/((K_(w))_(D_(2)O))=(1xx10^(-14))/(3xx10^(-15))=(10)/(36)=3.333`