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Normalhumanbody of thetemperatureis 98.6^(@)F. Duringhighfeverif thetemperatureincreasesto 104^(@)Fwhat is thechange in peakwavelengththatemittedby ourbody ? (Assumehumanbody is ablackbody) |
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Answer» Solution :Normal human body temperature `(T)=98.6^(@)F` `(F-32)/(180)=(K-273)/(100)` `"So,"T=98.6^(@)F=310K` From Wien.s displacement law Maximum wavelength, `lambda_("max")=(b)/(T )=(2.898xx10^(-3))/(310)=9348xx10^(-9)m` `lambda_("max")=9348nm""(" at "98.6^(@)F)` During high FEVER, human body temperature, `T=104^(@)F=313K` `"Peak wavelength"lambda_("max")=(b)/(T )=(2.898xx10^(-3))/(313)=9259xx10^(-9)m` `lambda_("max")=9259 nm""("at "104^(@)F)` |
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