1.

Normalhumanbody of thetemperatureis 98.6^(@)F. Duringhighfeverif thetemperatureincreasesto 104^(@)Fwhat is thechange in peakwavelengththatemittedby ourbody ? (Assumehumanbody is ablackbody)

Answer»

Solution :Normal human body temperature `(T)=98.6^(@)F`
`(F-32)/(180)=(K-273)/(100)`
`"So,"T=98.6^(@)F=310K`
From Wien.s displacement law
Maximum wavelength, `lambda_("max")=(b)/(T )=(2.898xx10^(-3))/(310)=9348xx10^(-9)m`
`lambda_("max")=9348nm""(" at "98.6^(@)F)`
During high FEVER, human body temperature, `T=104^(@)F=313K`
`"Peak wavelength"lambda_("max")=(b)/(T )=(2.898xx10^(-3))/(313)=9259xx10^(-9)m`
`lambda_("max")=9259 nm""("at "104^(@)F)`


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