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Normality of 0.2M sulphuric acid solution is ........ |
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Answer» 0.4 N Molecular weight `=2 + 32 + 64 = 98 g * mol^(-1)` Basicityof `H_(2)SO_(4) = 2` Equivalent weight of `H_(2)SO_(4)= 98//2=49.0. "equi"^(-1)` `N= "Molarity" xx "BASICITY"=0.2xx2= 0.4 N H_(2)SO_(4)` |
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