Normality of a '30 volume H_2O_2' solution is:

1.	Normality of a '30 volume H_2O_2' solution is:
Answer» 1.6 91.07 10.72 5.36 Solution :30 VOLUME `H+2O_2` MEANS that one litre of the sample GIVES 30 L of `O_(2)`at S.T.P. `underset(68 g)(2H_(2)O_(2)) to 2H_(2)O + underset("22.4 L at S.T.P")(O_(2))` The mass of `H_2O_2` which gives 30 L of `O_2` at S.T.P. `=68/(22.4) xx 30 = 91.07 g` THUS, one litre of the given sample contains 91.07 g of `H_(2)O_(2)`. `therefore w = (N xx E xx V)/1000` `therefore` Normality (N) `=(w xx 1000)/(E xx V)` `=(91.07 xx 1000)/(17 xx 1000) = 5.36 N`

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