Not considering the electronic spin , the degeneracy of the second excited state (n=3) of H atom is 9, while the degeneracy of the second excited state of H^- is

Not considering the electronic spin , the degeneracy of the second exc

1.	Not considering the electronic spin , the degeneracy of the second excited state (n=3) of H atom is 9, while the degeneracy of the second excited state of H^- is
Answer» Solution :Energy order of ORBITALS of H is decided by only principal quantum number (N) while energy order of `H^-` is decided by (n+l) rule ELECTRONIC configuration of `H^-` is `1s^2` its Energy order is decided by n+l rule `H^(-)=1s^2 2s^0 2p^0` Its `2^"nd"` EXCITED state is 2p and degeneracy 2p is '3'