1.

Nsub3 =(a) 16(b) 14(c) 12(d) 10I got this question during a job interview.Query is from Designing Subnets topic in portion Internet Protocol, Network Addressing and Transport Level Security of Cryptograph & Network Security

Answer»

Correct answer is (a) 16

Explanation: The number of addresses in the THIRD SUBBLOCK (10) is not a POWER of 2.

Thus, we allocate Nsub3 = 16 addresses.



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