1.

Nuclear attraction is often the deciding control factor for the association of neutral molecules to a given metal ion. Which onee of the following represents the correct order of stability of the ions? [Be(H_(2)O)_(4)]^(2+),[Mg(H_(2)O)_(4)]^(2+),[Ca(H_(2)O)_(4)]^(2+) and [Sr(H_(2)O)_(4)}^(2+)

Answer»

`[Be(H_(2)O_(4)]^(2+) GT [Sr(H_(2)O_(4)]^(2+)gt [Mg(H_(2)O)_(4)]^(2+) gt [Ca(H_(2)O)_(4)]^(2+)`
`[Ca(H_(2)O)_(4)]^(2+) gt [Mg(H_(2)O)_(4)]^(2+) gt [Be(H_(2)O)_(4)]^(2+) gt gt[S(H_(2)O)_(4)]^(2+)`
`[Sr(H_(2)O)_(4)]^(2+) gt [Ca(H_(2)O)_(4)]^(2+) gt [Mg(H_(2)O)_(4)]^(2+) gt [Be(H_(2)O)_(4)]^(2+)`
`[Be(H_(2)O)_(4)]^(2+) gt [Mg(H_(2)O)_(4)]^(2+) gt [Ca(H_(2)O)_(4)]^(2+) gt [Srr(H_(2)O)_(4)]^(2+)`

Solution :The DEGREE of HYDRATION and the amount of hydration energy decreases as the size of the ion increases from `Be^(2+)` to `Sr^(2+)`.
`{:(,Be^(2+)LT,Mg^(2+)lt,Ca^(2+)lt, Sr^(2+)),("Hydration Energy "(kJ" "mol^(-1)),-2494,-1921,-1577,-1443):}`
Thus, stability of hydrated ion is
`[Be(H_(2)O)_(4)}^(2+) t [Mg(H_(2)O)_(4)]^(2+) gt [Ca(H_(2)O)_(4)]^(2+)gt[Sr(H_(2)O)_(4)]^(2+)`


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