InterviewSolution
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InterviewSolution
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Nuclei of .^(64)Cu can decay be electron capture (probability 61%) or by beta^(+) decay (39%). Half life of .^(64)Cu is 12.7 hour. Find the partial half life for electron capture decay process, |
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Answer» `._(29)Cu^(64)rarr ._(30)ZN^(64) +._(-1)E^(0)` `beta^(+) "emission"` `._(29)Cu^(64) rarr ._(28)Ni^(64)+._(+1)e^(0)` Electron capture `.(29) Cu^(64)+_(-1)e^(0) rarr._(28)Ni^(64)` `% "of I product" = 38%=(lambda_(1))/(lambda_(1)+lambda_(2)+lambda_(3)) xx 100 =(lambda_(1))/(LAMBDA)xx100=((0.693)/((t_(1//2))_(1)))/((0.693)/(t_(1//2)))xx100` `lambda rArr` overall disintegration constant `(38)/(100)=((t_(1//2)))/((t_(1//2))_(1))` `:. (t_(1//2))=(t_(1//2))xx(100)/(38)=12.8 xx(100)/(38)=33.68 "hour"^(-1)` similarly `(t_(1//2))_(II)=(t_(1//2))xx(100)/(19)=12.8 xx(100)/(19)=67.36 "hour"^(-1)` `(t_(1//2))_(III)=(t_(1//2))xx(100)/(43)=12.8xx(100)/(43)=29.776 "hour"^(-1)` 
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