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Number of all possible enols of formula `C_(4)H_(8)O` are : |
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Answer» Correct Answer - 12 `CH_(2)=CH-CH_(2)-overset(OH)overset(|)CH-H to(1)` `CH_(3)-underset(H)underset(|)C=underset(H)underset(|)C=overset(OH)overset(|)CH_(2) to (2) "geometrical isomer"` `CH_(3)-CH_(2)-underset(H)underset(|)C=overset(OH)overset(|)C-H to(2)"geometrical"` `CH_(2)=overset(OH)overset(|)C-CH_(2)-CH_(3) to(1)` `CH_(2)=CH-underset(H)underset(|)overset(OH)overset(|)C"_(**)CH_(3) to (2) `enantiomer `CH_(3)-underset(H)underset(|)C=overset(OH)overset(|)C-CH_(3)-(2)` geometrical `H_(2)C=underset(CH_(3))underset(|)C=overset(OH)overset(|)C-H to (1)` `HC_(3)=underset(CH_(3))underset(|)C=overset(OH)overset(|)C-H to (1)` |
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