Number of atoms of iron present in 100 gm Fe_(2)O_(3) having 20% purit

1.	Number of atoms of iron present in 100 gm Fe_(2)O_(3) having 20% purity is
Answer» `0.2N_(A)` `0.25N_(A)` `0.5N_(A)` `0.3N_(A)` Solution :No. of mole of pure `Fe_(2)O_(3)=(20)/(160)` No. of FE atoms = `(20)/(100)xx2xxN_(A)=0.25N_(A)`.

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