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Number of atoms of oxygen present in 10.6 g of `Na_(2)CO_(3)` will beA. `6.02xx10^(22)`B. `12.04xx10^(22)`C. `1.806xx10^(23)`D. `31.80xx10^(28)` |
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Answer» Correct Answer - C Molar mass of `Na_(2)CO_(3) = 2xx23+1216xx3` `=46+12+48` `=106gmol^(-1)` `:.` 10.6 g of `Na_(2)CO_(3)-=0.1` mol of `Na_(2)CO_(3)` `=0.3` mol of oxygen atoms `=0.3xx6.02xx10^(-23)` oxygen atom `=1.806xx10^(23)` oxygen atom |
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