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Number of Faradays required to reduce `3 mol` of `MnO_(4)^(c-)` to `MnO^(2+)` is `……………………….F` |
Answer» Correct Answer - `(15F)` `(15F)` `8H^(o+)+5e^(-) +MnO_(4)^(c-) rarr Mn^(2+)+4H_(2)O ` `1 mol` of `MnO_(4)^(c-) -=5e^(-)=5F`. `3 mol `of `MnO_(4)^(C-)=5xx3=15F` |
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