Number of HIO4 required to cleave the moleculeCH2-OH|CH-OH|C=O|CH2-OH

1.	Number of HIO4 required to cleave the moleculeCH2-OH\|CH-OH\|C=O\|CH2-OH
Answer» Answer: Oxidation-reduction · 1,2- or VICINAL diols are CLEAVED by periodic ACID, HIO4 , into two CARBONYL compounds

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Answer:

Oxidation-reduction · 1,2- or VICINAL diols are CLEAVED by periodic ACID, HIO4 , into two CARBONYL compounds

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